PDC (Pyridinium dichromate)-oxidizing agent

Oxidize primary and secondary alcohol to aldehyde and ketones.

Also known as Cornforth reagent.

PDC is less acidic than PCC. Therefore, more suitable for the oxidation of acid-sensitive groups.

Appearance: red/orange solid

Properties: soluble in water, DMF, DMSO and dimetyllactamide. Sparingly soluble in DCM.

Preparation:

Examples:

PCC (Pridinium chlorochromate)- oxidizing agent

Widely used for oxidation of primary and secondary alcohol.

Particularly for oxidizing primary alcohol to aldehyde . Does not effect any double bond.

Appearance: yellow orange solid

Properties: it is not hygroscopic and can be used in stoichiometric amount.

Preparation:

Examples:

for detailed Mechanism:

       click here to download pdf

Collin’s reagent-oxidizing agent

Collin’s reagent

Selectively oxidize primary alcohol to aldehyde in organic solvents.

Appearance: red crystals

Preparation: generated “in situ”

EXAMPLES:

Limitations:

Highly hygroscopic 

CHROMIUM BASED REAGENTS -Chromic acid (H2CrO4)

Chromium based reagents
 Chromic acid (H₂CrO₄)

Commonly used for oxidation of primary and secondary alcohols that do not contain acid sensitive group.

Appearance: dark red crystals

Preparation: often prepared “in situ”

Examples:

Mechanism:

Limitations:

  High toxicity.

 Saturated primary alcohols are oxidized to carboxylic acid.

CLICK  HERE TO DOWNLOAD PDF

WELCOME

My dear , friends and students you are hearty welcome to "competitive chemistry exams".

intention of creating this blog is every one should clear a many competitive exams in chemistry field. also every students receive a quality of chemistry knowledge  i sure that this blog is very beneficial for your exam preparation. every weekend, we will conducting tests in online or practice a exam point of view of questions. discussion is extremely very power full than other, if we use it in correct way. so utilize your time . we will definitely place in good position. unity is strength friends. if you are interested kindly reply me topic of discussion.